Question

tanθ=-√7/3 and θ is in quad IV. Find secθ

Answer 1

\[\sec^2\theta= 1+\tan^2\theta\]

Answer 2

sec is positive in fourth quad, just put the value and take the sqrt

Answer 3

4/3?

Answer 4

right

Answer 5

thank you

Answer 6

Another slant:
\[\text{Sec}\left[\text{ArcTan}\left[-\frac{\sqrt{7}}{3}\right]\right]=\frac{4}{3} \]