Question

A farmer has 3 children and a herd of 30 cows. He gives 15 cows to his oldest child and 5 cows to his youngest child. Find the number os ways the farmer can split up his herd

Answer 1

it's permutations and combinations we are on

Answer 2

\({30 \choose 15}{15 \choose 5}=\frac{30!}{15!15!}\frac{15!}{10!5!}\)

Answer 3

thanks so much