The sum of three consecutive even integers is -24. Find the integers.

Question

watchmath · Answer

The same idea spoyled. Why don't you give it a try first? :D

anonymous · Answer

I dont understand this at all. Hoping to look at these and try to comprehend. These are all my practice exercises.

watchmath · Answer

Ok, if the smallest number among the three is $n$. Then the next even number is $n+2$ and the next after that is $n+2+2=n+4$.
So the sum of these three even numbers is
$n+(n+2)+(n+4)=3n+6$
we want this sum to be equal to -24. So $3n+6=-24$
$3n=-30$
$n=-10$
So the next two even numbers are -8, -6. Thus -10,-8,-6 are the answers.

radar · Answer

Les 2x = 1st integer
2x + 2 = 2nd
2x+4 = 3rd even integer
the sum is -24 so
2x+2x+2+2x+4=-24
6x=-24-6=-30
x=-5
2x=-10
2x+2=-8
2x+4=-6

Making first digit equal 2x assures it is even.
the next one is also even so it is 2x+2

anonymous · Answer

thank you and that helps to understand process little better