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a car agency has 10 midsize cars and 16 compact cars on it's lot,from which 6 will be selected. assuming that each car is euqally likely to be selected and the cars are selected at ramdom, determine the problablity that all cars that are selected are midzise?
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10C6/26C6
10*9*8*7*6 and then the same to 26?
26*25*24*23*22*21? right?
the firstv one divide by 4! and the second one divide by 20!
what u deviding the answer u get after u multiply?
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see ill tell u fr d first nd last tym nCr means n!/r!(n-r)!
does it come out to 30240/165765600?
did u divide like i told u?
10 devides by 4 or 30240 does?
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