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OpenStudy (anonymous):
0 + (root5)i
OpenStudy (anonymous):
is that the answer?
OpenStudy (anonymous):
yes i think so
OpenStudy (anonymous):
so i put o+√5
OpenStudy (anonymous):
0+√5
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OpenStudy (anonymous):
√-1 *√-52 =i2√13
OpenStudy (anonymous):
i2√13 is the answer?
OpenStudy (anonymous):
sorry missing side
√-1 *√52 = i2√13
yes
OpenStudy (anonymous):
i for negative side
OpenStudy (anonymous):
thank
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OpenStudy (anonymous):
what??? i-
OpenStudy (anonymous):
when the root negative
OpenStudy (anonymous):
can you type how my answe is going to look
OpenStudy (anonymous):
√-52 =√-1=√-1
√-1= i
=√52 = 2*2*13 = 2√13
than a answer is : 2i √13
or u can write : - 2√13
it mean negative put out side,keep radical square positive side
OpenStudy (anonymous):
okay so what about this one ? √-18
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OpenStudy (anonymous):
sorry I keep tye wrong again
√-52 =√-1*√52
√-1= i
=√52 = 2*2*13 = 2√13
than a answer is : 2i √13
or u can write : - 2√13
it mean negative put out side,keep radical square positive sidea minute ago