Question

one more please.
the length of a rectangle is 3 feet longer than its width. determine the length and width of the rectangle if its area is 40 square feet.

Answer 1

L=W+3
A=L*W=(W+3)W=W^2+3W
So W^2+3W=40
W^2+3W-40=0
(W+8)(W-5)=0
W=-8 or W=5
Since W is positive, then W=5
Then L=W+3=5+3=8.

Answer 2

yay!!!! thank you :)

Answer 3

Hit the good answer to give me a medal if you like :D