Question

Situation:
a 48 gram sample of substance that's used for drug research has a k-value of 0.1325.

Find the substance's half-life, in days. Round your answer to the nearest tenth

Answer 1

same as last one
\[\frac{1}{2}=e^{-.1325t}\]
\[ln(.5)=-.1325t\]
\[t=\frac{ln(.5)}{-.1325}\]
\[t=5.23\]

Answer 2

i guess in general you can see that the answer will be
\[\frac{ln(.5)}{-k}\]