Question

Three lockers are numbered consecutively (n,n+1,n+2) in such a way that the sum of the first and last lockers is the same as twice the middle locker number. What are the locker numbers?

Answer 1

n + n + 2 = 2(n + 1)
2n + 2 = 2n + 2

essentially... any three consecutive numbers works. try,

(5,6,7) 5 + 7 = 2 * 6
(20,21,22) 20 + 22 = 2(21)

Answer 2

ty

Answer 3

ty