Question

solve for x: 3 over x-2 + 8 over x^2 - 4 = 1

Answer 1

3 8
---- + -------- = 1
x - 2 x^2 - 4

First you need a common denominator to put on top of each term.. common denominator is (x + 2)(x - 2)

(x + 2)(x - 2)*3 (x + 2)(x - 2) * 8 (x + 2)(x - 2) * 1
------------- + --------------- =
x - 2 x^2 - 4

Answer 2

Cancel the denominators into the numerators.

Answer 3

(x + 2) * 3 + 8 = (x + 2)(x - 2)

Answer 4

3x + 6 + 8 = x^2 - 4
3x + 14 = x^2 - 4

0 = x^2 - 3x - 18
0 = (x - 6)(x + 3)
x = 6 or x = -3

Answer 5

\[3/(x-2) + 8/(x^2-4) = 1\]
\[3*(x+2)/(x^2-4) +8/(x^2-4) = 3x + 14/(x^2-4) = 1\]
\[3x+14 = x^2 -4; x^2-3x-18 = (x-6)(x+3) = 0\]
x = -3 or x = 6

Answer 6

thank you :))