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Mathematics 26 Online
OpenStudy (anonymous):

Solve: sec²θ = 2tanθ+4 over the interval [0,2pi)

OpenStudy (anonymous):

\[\sec ^{2}\Theta=1+\tan ^{2}\theta\] substitute & solve it as quadratic equation for tan

OpenStudy (anonymous):

i got as far as (x+1)(x-3) =tan²=-1 and tan²=3 but I don't know what to do next?

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