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An object travels half its total path in the last second of its fall from rest. Find the following: A) Total time it falls B) The height of its fall
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Time to fall \[t=\sqrt{2h/g}\] Height of fall: \[h=1/2(g)(t)^{2}\div2\]
Where g = 9.8m/s^2, t = time, and h = height.
Thank you!
Assuming the only force considered is gravity for practical purposes; By this we mean ignoring air resistance, earth magnetic field and any other existing external forces.
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