Question

Situation:
A 11 gram sample of a substance that's used to treat thyroid disorders has a k-value of .125.
find the substance's half-life, in days. round to the nearest tenth

Answer 1

.125^t=.5
find t

Answer 2

how do i find t ?

Answer 3

log form

Answer 4

explain? or show me?

Answer 5

\[\log_ab=c\]
can be written as
a^c=b

Answer 6

your formula is .125^t=.5
so
\[\log_{.125}.5=t\]

Answer 7

1.5 ?

Answer 8

how's you get that?

Answer 9

is .5 a exponent?

Answer 10

no

Answer 11

i just got 1.4 now

Answer 12

log .5/ log .125

Answer 13

.33 is what i just got

Answer 14

that's right