Question

find the value of x
logx+log(2x-1)=0

Answer 1

log(x) + log(2x-1) = 0
log (x*(2x-1))= 0
10^0 = 2x^2 - x
2x^2 - x -1 =0
(2x+1)(x-1) = 0
x = -1/2 or 1
x cannot be -1/2 (because it would cause log(2x-1) = log(0)
Therefore, x = 1

Answer 2

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