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OpenStudy (anonymous):
i need help solving x2 -4x +3 =0 by completing the square
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OpenStudy (anonymous):
x^2-4x=-3 x^2-4x+4=-3+4 (x-2)^2=1 x-2=+/- 1
OpenStudy (anonymous):
\[x ^{2} - 4x + 3 = 0\] x^2 - 4x = -3 x^2 -4x + 4 = -3 +4 (x-2)^2 = 1 x - 2 = + or - 1
OpenStudy (anonymous):
thanks
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