Question

i missed my class... how do i solve this?

Square root of 110 - n(110 and - n are all under the sqr root) =n

so Sqr of 110 -n = n

Answer 1

sqrt(110-n)=n
110-n=n²
n²+n-110=0
(n+11)(n-10)=0
n+11=0 or n-10 = 0
n=-11 or n=10

Answer 2

\[\sqrt{110 - n} = n\]