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Jan is five years older than Leann. Three years ago, the sum of their ages was 35. Find the age of each. How do I solve this?
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J=L+5 (Jan five years older than Leann) (J-3)+(L-3)=35 (3 years ago the sum of their ages was 35) J-L=5 J+L=41 add the equations 2J=46 J=23 L=18
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