The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

Question

anonymous · Answer

use distanace formula to find radius

toxicsugar22 · Answer

Cnu help me

anonymous · Answer

D from C to P = $$\sqrt{3^2+2^2} = \sqrt{13}$$
$$(x-2)^2 + (y-4)^2 = 13$$

toxicsugar22 · Answer

ok is this the answer

anonymous · Answer

Yes :D

toxicsugar22 · Answer

i think we write in in slope intecept form

toxicsugar22 · Answer

so what would that be

anonymous · Answer

You can only write a line in slope-int form, not a circle :D

toxicsugar22 · Answer

ok

toxicsugar22 · Answer

thanks can u help me with this one

toxicsugar22 · Answer

sketch the triangle with vertics A(-5,12), B(4,-2) and C(1,-6)

Find the slope of the side AC.

Find the slope of the altitude form point B to side AC

fIND an equation for the line that includes the altitude from point B to side AC.