Question

The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

Answer 1

use distanace formula to find radius

Answer 2

Cnu help me

Answer 3

D from C to P = \[\sqrt{3^2+2^2} = \sqrt{13}\]
\[(x-2)^2 + (y-4)^2 = 13\]

Answer 4

ok is this the answer

Answer 5

Yes :D

Answer 6

i think we write in in slope intecept form

Answer 7

so what would that be

Answer 8

You can only write a line in slope-int form, not a circle :D

Answer 9

ok

Answer 10

thanks can u help me with this one

Answer 11

sketch the triangle with vertics A(-5,12), B(4,-2) and C(1,-6)

Find the slope of the side AC.

Find the slope of the altitude form point B to side AC

fIND an equation for the line that includes the altitude from point B to side AC.