Question

what are the foci of the graph 4X^2-9Y=36? ....

Answer 1

solve for y
y = 4/9 x^2 -4
vertex: (0,-4)
foci is -4 + 1/(4*4/9)
foci: (0,-55/16)

Answer 2

possible answers are ((plus minus)6,0), ((plusminus) 3.6, )) , (0, (plus minus)6) , or (0, (plusminus 3.6))

Answer 3

hmm..this must be a hyperbola then
you mistyped the question
4x^2 -9y^2 = 36
x^2/9 - y^2/4 = 1
center: (0,0)
a^2=9
b^2=4
c^2 = 9+4=13
c = sqrt(13) = 3.6
foci: (0, +-3.6)