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Mathematics 13 Online
OpenStudy (anonymous):

evaluate 1+2+4+8 to S (small) 10

OpenStudy (anonymous):

You mean until the 10th term of the series?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

There is a cool expression that goes: \[\sum_{0}^{n}(2^n) = 2^{n+1} - 1\] So the answer is 2^10 - 1 = 1023

OpenStudy (anonymous):

what would i do without you

OpenStudy (anonymous):

You would use satellite :D

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