Question

1.put the equation 2y-3x=5 into slope intercept form

2.use the point slope formula to write an eqaution for the line that is perpendicular to the graph of 2y-3x=5 and passes through the point (1,4)

Answer 1

Slope-int form: y = mx +b
2y-3x = 5
2y = 3x +5
y = 3x/2+5/2

2. m = 3/2 Perpendicular slope = -2/3
y - 4 = (-2/3)(x-1)

Answer 2

thanks