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I am a hard time with this one. Can someone show me the steps please: 6y^2-22y-40
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Are you looking to factor it? If so:\[2(3y^2 - 11y -20)\]\[(3y +4)(y-5)\]
I forgot the two, put it in :D
I am looking to solve =0
All you do then is say that y = -4/3 or y = 5 :D
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