Question

i^(50)

Answer 1

that is i as in \[\sqrt{-1}\]?

Answer 2

\[i^1=i\]
\[i^2=-1\]
\[i^3=-i\]
\[i^4=1\]

Answer 3

then the pattern repeats
i, -1,-i, 1, i, -1, -i, 1, ... every 4. so just divide 50 by 4

Answer 4

you get a remainder of 2, so \[i^{50}=i^2=-1\]