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Mathematics 8 Online
OpenStudy (anonymous):

and!! 7b-1/b2+b-2 (subtract) 6/b-1

OpenStudy (anonymous):

\[(7b-1)/(b^2+b-2) - 6/(b-1) = (7b-1)/((b+2)(b-1) - b/(b-1)\]\[(7b-1+6b+12)/((b+2)(b-1)) = (13b+11)/((b+2)(b-1))\]

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