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OpenStudy (anonymous):
and!! 7b-1/b2+b-2 (subtract) 6/b-1
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OpenStudy (anonymous):
\[(7b-1)/(b^2+b-2) - 6/(b-1) = (7b-1)/((b+2)(b-1) - b/(b-1)\]\[(7b-1+6b+12)/((b+2)(b-1)) = (13b+11)/((b+2)(b-1))\]
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