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Mathematics 19 Online
OpenStudy (anonymous):

int_{-2}^{1}(4z+1)(4z-1)dz . Can somebody calculate this integral?

OpenStudy (anonymous):

16z^3 / 3 - z

OpenStudy (anonymous):

i need detailed calculation proces.

OpenStudy (amistre64):

\[\int\limits_{-2}^{1} (4z+1)(4z-1)dz\] this thing right?

OpenStudy (anonymous):

Yes

OpenStudy (amistre64):

multiply the 2 together and doa regualr integration of sums

OpenStudy (amistre64):

\[\int\limits_{-2}^{1} (16z^2 -1)\]

OpenStudy (anonymous):

Thanks.

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