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int_{-2}^{1}(4z+1)(4z-1)dz . Can somebody calculate this integral?
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16z^3 / 3 - z
i need detailed calculation proces.
\[\int\limits_{-2}^{1} (4z+1)(4z-1)dz\] this thing right?
Yes
multiply the 2 together and doa regualr integration of sums
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\[\int\limits_{-2}^{1} (16z^2 -1)\]
Thanks.
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