Question

If you have a 4 sided polygon wit the bottom left corner 60 degrees, top left 102 degrees, and the bottom right 70 degrees, how do you find the exterior angle on the right corner?

Answer 1

Let the angles be A,B,C&D
A=60
B=102
C=70
D=?

Now A+B+C+D=360.

Now, x what is shown in the diagram is infact not an exterior angle but vertically opposite angle to D and will be equal to D

Thus x would be 360-(A+B+C)
=360-(232)
=128.