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write it in the form of a+ib (1+i)2(1-i)3 1+i square and 1-i cube
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\((1+i)^2(1-i)^2(1-i)=2^2(1-i)=4-4i\)
1+i is square and 1-i is cube
Yes, but we can write \((1+i)^3\) as \((1+i)^2(1+i)\) right ?
I mean \((1-i)^3=(1-i)^2(1-i)\)
my answer comes-4+4i
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How did you get that?
thanx a lot for the help:)
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