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Mathematics
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a.derivative 6x^3- (4/x^-2) + cuberoot x2
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\(f(x)=6x^3-4x^2+x^{2/3}\) \(f'(x)=18x^2-8x+\frac{2}{3}x^{-1/3}\)
18x^2- 8/3 + 1/x wait is it the cuberoot of 2x or x^2?
18x^2-8x+1/x***
if it's the cuberoot of 2x....... the answer is \[18x ^{2} -8x + 2/3x ^{-2/3}\]
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