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Mathematics 14 Online
OpenStudy (anonymous):

find the product of (2n+2)(6n+1) pleeeease<33

OpenStudy (anonymous):

Do you know how to do FOIL? lol

OpenStudy (anonymous):

\[12n^2+8n+2\]

OpenStudy (anonymous):

first, inside, outside, last? is that what it stands for. i just dont know how to do it.

OpenStudy (anonymous):

Yeah, that's it It's the product of the first number of each part (2n and 6n) plus the product of the outside numbers of each part (2n and 1) plus the product of the inside numbers (2 and 6n) plus the product of the last numbers (2 and 1)

OpenStudy (anonymous):

Haha ya he got to it first (: Thats exactly it lol

OpenStudy (anonymous):

lol, alright thanks guys. :)

OpenStudy (anonymous):

weeelcoooomeeee!!! (:

OpenStudy (anonymous):

okay so, i get how you got the 12n part in the answer.. but not the other parts..

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