Question

Solve the following systems of equations algebraically:

2y=8-x
y-2x=-1

The solution is x=?, y=?

Answer 1

2y = 8-x we can get x = 8- 2y
y-2(8-2y)=-1
y-16+4y= -1
5y = 15
y=3
2*3=8-x
6= 8-x
x=2