Question

solve the intial value problem..
y' = (xy)^(1/2), y(0) = 1
how would you seperate x and y..??

Answer 1

\[{dy \over dx}=x^{1/2}y^{1/2} \implies {dy \over y^{1/2}}=x^{1/2}dx\]

Answer 2

Just integrate both sides, and then solve for the initial value.

Answer 3

oo i wasnt sure if we can pull them apart like that..