Question

use quadratic formula: x^2 - 15 = 3x
PLEASE HELP!!!

Answer 1

first set = 0 via
\[x^2-3x-15=0\]
\[(x-5)(x+3)=0\]
\[x-5=0\]
\[x=5\]
or \[x+3=0\]
\[x=-3\]

Answer 2

oops sorry
quadratic formula! hello daniel

Answer 3

my answer is wrong wrong wrong

Answer 4

\[Quadratic formula: x = (-b \pm \sqrt{b^2-4ac})/2a\]
a = 1
b = -3
c = -15
\[x = (3\pm \sqrt{69})/2 \]

Answer 5

i will bow out and let daniel reply. his answer will be correct. this one does not factor over integer.

Answer 6

His answer "will be" correct? :D

I love you satellite :D

Answer 7

feeling is mutual (in a platonic kinda way)

Answer 8

Thanks Guyss =)

Answer 9

Who the heck is Platonic?

Just kidding :D

Answer 10

a solid fellow

Answer 11

^ I was kidding :D

Answer 12

What's The Final Answer though? i Don't Have A Calculator =/

Answer 13

x = 5.65331193 or x = -2.65331193