Question

√72+√32+√18

Answer 1

\[\sqrt{72} = 6\sqrt{2}\]\[\sqrt{32} = 4\sqrt{2}\]\[\sqrt{18} = 3\sqrt{2}\]\[6\sqrt{2} + 4\sqrt{2}+3\sqrt{2} = 13\sqrt{?}\]

Answer 2

\[13\sqrt{2}\]

Answer 3

Latex error :D

Answer 4

\[\sqrt{36*2}*\sqrt{16*2}*\sqrt{9*2}=6*4*3*\sqrt{8}=6*4*3*2*\sqrt{2}=144\sqrt{2}\]

Answer 5

woops sorry

Answer 6

thought you were being a teacher. class...CLASS...