Question

Solve the following system of equations.

x + y – 4z = –7
2x + 3y – 3z = –6
2x + 2y – z = 0

Answer 1

-2*first + second:\(y+5z=8\)
-2*first+third: \(7z=14\)
Hence \(z=2\)
\(y+10=8\)
\(y=-2\)
\(x-2-8=-7\)
\(x=3\)