Question

literal equation
A=1/3h(a+4b+c)
A=20; h=5; a and c =1
solve for b

Answer 1

literal equation
A=1/3h(a+4b+c)
A=20; h=5; a and c =1
solve for b

I'm really confused now. I've already looked at some examples

Answer 2

can anyone get me started?

Answer 3

did any one solve this yet?

Answer 4

not sure if it was \[A=\frac{1}{3}h(a+4b+c)\]or
\[A=\frac{1}{3h(a+4b+c)}\]