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Write an equation for the line with the given attributes. Write your answer in slope-intercept form if possible: Horizontal and passing through the point (-3,8)
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Since the line is horizontal then the slope is \(m=0\). Then the line is of the form \(y=0x+b\), i.e., \(y=b\).Since the line passes through \(-3,8\), then \(y=8\) is the line that we are looking for.
I'm not sure how to write that out into an equation....
Well it says that write in the slope intercept form if it is possible. In this case we can't write it as \(y=mx+b\) the slope \(m=0\). So in our equation there is no \(x\) variable and the equation of the line is just. \(y=8\)
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