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the equation is 4r[2]-2r=0 [2] Means square root in the equation
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r=0
\(4r^2-2r=0\), take 2r as a common factor, you get \(2r(2r-1)=0\). So r is either \(0\) or \(1/2\).
[2] is square root.
Is the question, \[4r \sqrt{2} - 2r =0\]
Yes that is the question
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Whoops, sorry for the misunderstanding :D
It's ok
So if you take out r, the only possibility is r=0
Thank you very much for your help!!
welcome :)
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