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what are the foci of the graph 4x^2-9y^2=36 a.(+-6,0) b.(0,+-6 c.(+-3.6,0) d.(0,3.6)
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4/36 = 1/9 ; -9/36 = -4 a = 3 and b = 4, the foci should be at 5 from center then
3 and 2 sorry lol
sqrt(9+4) = sqrt(13) for c
im thinking it c
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