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which is an equation of the line passing through (3,9) with a slope -2/3?
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point slope formula: \[y-y_1=m(x-x_1)\]
\[y-9=-\frac{2}{3}(x-3)\]
o in understand now thanks so much!
Equation of line: y = mx + c. m = 2/3 (known). Plug in known point: 9 = (2/3) * 3 + c ==> solve for c.
(or m = -2/3. can't tell due to line break in your question)
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