Question

Solve the equation
4x^2-28x+40=0

Answer 1

Divide through by 4

Answer 2

4x^2-28x+40=0
4(x^2-7x+10)=0
4(x-5)(x-2)=0 Divide thia equation by 4 and you get:
(x-5)(x-2)=0
x-5=0
x=5

x-2=0
x=2

Therefore, x=5 and x=2