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OpenStudy (anonymous):
Solve the equation 4x^2-28x+40=0
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OpenStudy (anonymous):
Divide through by 4
OpenStudy (anonymous):
OpenStudy (gw2011):
4x^2-28x+40=0 4(x^2-7x+10)=0 4(x-5)(x-2)=0 Divide thia equation by 4 and you get: (x-5)(x-2)=0 x-5=0 x=5 x-2=0 x=2 Therefore, x=5 and x=2
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