Question

Solve the equation. Express radicals in simplest form.
2m^2+12m+1=0

Answer 1

Answer=( -12+136^1/2)/4=-3 +(34^1/2)/2
and also -3 - (34^1/2)/2

Answer 2

\[m=\frac{-12 \pm \sqrt{12^2-4(2)(1)}}{2(2)}\]
\[\implies m=\frac{-12\pm 2\sqrt{34}}{4}\]

Answer 3

Use the quadratic formula:

x=[-b+/-square root (b^2-4ac)]/2a

a=2
b=12
c=1
x=m

m=[-12+/-square root (12^2-4*2*1)]/(2)(2)

m=[12+/-square root (144-8)]/4

m=[-12+/-square root (136)]/4=[12+/-square root 4*34]/4

m=[-12+/-(2*square root 34)]/4

m=[-6+/-(square root 34)]/2

m=(-6+square root 34)/2 and m=(-6-square root 34)/2