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can someone help me with qs 4 please???
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\[\sqrt{4}?\]
from this link http://www.ocr.org.uk/download/pp_10_jun/ocr_57857_pp_10_jun_gce_475201.pdf
I don't know sorry
you can find the actuallyy functions for them
because you know f(x)
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F(x)=(x^2-5x) f(2x)=(4x^2-10x)=4x(x-2.5) now the intersection points will be 0 and 2.5 instead of 0,5
for 3f(x) you have to multiply 3 with the ordinates of that points. Now you can draw it.
the multiply by 3 would it be 3x^2-15x???
yes.
but that o and 5 again and in the mark scheme it says minimum points and there different to 0, 2.5 and 0,5
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im confused :S
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