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OpenStudy (anonymous):
How do you find f^-1 of f(x)=(x+1)^2-6, with x< or = to -1
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OpenStudy (anonymous):
y = root(x+6) -1
OpenStudy (anonymous):
find out x as a fn of y and then interchange x and y
OpenStudy (anonymous):
yeah, I know. I doing this on Wamap and it keeps telling me my answers are wrong for these.
OpenStudy (anonymous):
I just wanted to see it worked out to see if it was me or wamap.
OpenStudy (anonymous):
It's ok, thanks
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