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OpenStudy (anonymous):
if in a triangle ABC, cosA.cosB+sinAsinBsinC=1, then the triangle is
a) right angled
b) equilateral
c)isosceles
d)none
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OpenStudy (anonymous):
a)
use A=B and C=90
u get (sinA)^2+(cosA)^2=1 which is an identity!
OpenStudy (anonymous):
its not necessary that A should be equal to B right?
OpenStudy (anonymous):
the answer is d
OpenStudy (anonymous):
that gives a 45-90-45 triangle.
i JUst tested a PARTICULAR case
the answer should hold for all cases!!
OpenStudy (anonymous):
k. then guessing wont work..
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OpenStudy (anonymous):
you want to see the solution?
OpenStudy (anonymous):
yups...
OpenStudy (anonymous):
why ask if u know the solution?
OpenStudy (anonymous):
because i dont understand them.
OpenStudy (anonymous):
why dont u use transformation formulae with the result A+B+C=180
that will give you the answer.
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OpenStudy (anonymous):
okay i got that one cleared up...thanx
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
jus took out sinC from the relation.. that led to to the conclusion that A=B
and finally C=90
the answer should be a
its misprinted here i guess
OpenStudy (anonymous):
well guess was right. It had to be right you know!!
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