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Simplify the expression cos^2 x -------- 1 + sin x A) 1 - sin x B) tan^2 x C) sec^2 x D) 1 E) 1 + cos x
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hint: \(\cos^2 x+\sin^2x =1\)
Which gives me 1 - sin^2x ----------- 1 + sinx but i'm not sure where to go from there
good! notice that the top is a difference of two squares.
so we can factor the top :D.
which gives me (1-sinx)(1+sinx) -------------- 1+ sinx which = 1- sinx
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So is the answer just A?
perfect! :D
Thanks!
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