Mrs. AYer IS PAINTING THE OUTSIDE OF HER SON'S TOY BOX, INCLUDING THE TOP AND BOTTOM. tHE tOY BOX MEASURES 3 FEET LONG, 1.5 FEET WIDE, AND 2 FEET HIGH. whAT IS THE TOTAL SURFACE AREA SHE WILL PAINT?

A) 9.0 FT^2
B) 13.5 FT^2
C) 22.5 FT^2
D) 27.0 FT^2

Question

Mrs. AYer IS PAINTING THE OUTSIDE OF HER SON'S TOY BOX, INCLUDING THE TOP AND BOTTOM. tHE tOY BOX MEASURES 3 FEET LONG, 1.5 FEET WIDE, AND 2 FEET HIGH. whAT IS THE TOTAL SURFACE AREA SHE WILL PAINT?

A) 9.0 FT^2
B) 13.5 FT^2
C) 22.5 FT^2
D) 27.0 FT^2

anonymous · Answer

SO WOULD YOU HAVE TO MULTIPLE THE DIFFERENT MEASUREMENTS?

anonymous · Answer

3*1.5=4.5ft
2*4.5 = 9ft    ( Area bottom an top )
   3*2 = 6
     2*6=12    (Area bottom 2 side)
  1.5*2=3ft
 2 * 3 = 6     (Area front  an back)
9+12+6=27ft

anonymous · Answer

wait I was wrong

anonymous · Answer

3*1.5=4.5ft
2*4.5 = 9ft    ( Area bottom an top )
   3*2 = 6
     2*6=12    (Area  2 side)
  1.5*2=3ft
 2 * 3 = 6     (Area front  an back)
9+12+6=27ft

anonymous · Answer

D)
If I deserve medal then give me one

anonymous · Answer

u were right:)