Question

Suppose that a certain straight line has vector equation
u(t) = ‹ 4+2t, 2+6t, 6+9t › .
Enter a vector (using numbers and commas only) that is parallel to this line:

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Answer 1

2t,6t,9t is the vector of this equation; the 4,2,6 is a point. all you need to do is keep the same vector parts, but change the point values

Answer 2

<2,6,9> i think is what they want