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solve 6+(2x-7)^2/3=31 (two answers)
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ok are you sure it is to the power or 2/3?
yes
ok \[(2x-7)^{\frac{2}{3}}=25\] \[2x-7=25^{\frac{3}{2}}\] \[2x-7=125\] \[2x=118\] \[x=59\]
ops \[2x
\[2x-7=125\] \[2x=132\] \[x=66\]
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sorry. other one \[2x-7=-125\] \[2x=-118\] \[x=-59\]
okay thats right
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