Question

√x+7( 14 years ago

Answer 1

x=2
x=9

Answer 2

\[\sqrt{x+7}+5=x\]\[\sqrt{x+7}=x-5\]\[(\sqrt{x+7})^{2}=(x-5)^{2}\]\[x+7=(x-5)(x-5)\]\[x+7=x ^{2}-10x+25\]\[x^{2}-10x+25-x-7=0\]\[x^{2}-11x+18=0\]

fractor:\[(x-9)(x-2)\]
x=9
x=2