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Mathematics 11 Online
OpenStudy (anonymous):

Find the derivative of x^2+ 3x tg x

OpenStudy (anonymous):

tg ?

OpenStudy (anonymous):

Sorry about tg, it´s a tang.

OpenStudy (watchmath):

\(2x+\sec^2 x\)

OpenStudy (anonymous):

tang? think u mean tan :|

OpenStudy (anonymous):

tg is the same of tangent

OpenStudy (watchmath):

oh sorry ... :) go ahead elcengineer ...

OpenStudy (anonymous):

and in that case u need product rule on second term

OpenStudy (anonymous):

\[2x + 3 ( x \sec^2(x) + \tan(x))\]

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