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solve (x+3)^3/2-11=53
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\((x+3)^3=64\) \((x+3)^3=4^3\) \(x+3=4\) \(x=1\)
53 not 64
after you move over the 11 you get 64
okay
ok but I made a mistake
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\((x+3)^{3/2}=64=4^3=16^{3/2}\) \(x+3=16\) \(x=13\)
yeah because the first answer wasn't up there but that one is
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